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title: 字符串的排列 date: 2019-08-21T11:00:41+08:00 draft: false categories: offer
题目
解题思路
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public ArrayList<String> Permutation(String str) {
Set<String> res = new HashSet<>();
if (str == null || str.length() == 0) {
return new ArrayList<>();
}
Permutation(res, str.toCharArray(), 0);
ArrayList<String> list = new ArrayList<>(res);
list.sort(String::compareTo);
return list;
}
private void Permutation(Set<String> res, char[] chars, int start) {
if (start == chars.length) {
res.add(new String(chars));
return;
}
for (int i = start; i < chars.length; i++) {
swap(chars, start, i);
Permutation(res, chars, start + 1);
swap(chars, start, i);
}
}
private void swap(char[] chars, int i, int j) {
char temp = chars[i];
chars[i] = chars[j];
chars[j] = temp;
}